3y^2+40y-28=

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Solution for 3y^2+40y-28= equation:


Simplifying
3y2 + 40y + -28 = 0

Reorder the terms:
-28 + 40y + 3y2 = 0

Solving
-28 + 40y + 3y2 = 0

Solving for variable 'y'.

Factor a trinomial.
(-14 + -1y)(2 + -3y) = 0

Subproblem 1

Set the factor '(-14 + -1y)' equal to zero and attempt to solve: Simplifying -14 + -1y = 0 Solving -14 + -1y = 0 Move all terms containing y to the left, all other terms to the right. Add '14' to each side of the equation. -14 + 14 + -1y = 0 + 14 Combine like terms: -14 + 14 = 0 0 + -1y = 0 + 14 -1y = 0 + 14 Combine like terms: 0 + 14 = 14 -1y = 14 Divide each side by '-1'. y = -14 Simplifying y = -14

Subproblem 2

Set the factor '(2 + -3y)' equal to zero and attempt to solve: Simplifying 2 + -3y = 0 Solving 2 + -3y = 0 Move all terms containing y to the left, all other terms to the right. Add '-2' to each side of the equation. 2 + -2 + -3y = 0 + -2 Combine like terms: 2 + -2 = 0 0 + -3y = 0 + -2 -3y = 0 + -2 Combine like terms: 0 + -2 = -2 -3y = -2 Divide each side by '-3'. y = 0.6666666667 Simplifying y = 0.6666666667

Solution

y = {-14, 0.6666666667}

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